Simmons Named Most Improved
Posted May 2 2005 2:19PM
Former NBDL player outpaces Miami's Wade for honor
NEW YORK, April 28 -- Bobby Simmons of the Los Angeles Clippers was named the winner of the 2004-05 NBA Most Improved Player Award, the NBA announced today. The annual award is presented to a player who has made a dramatic improvement from the previous season or seasons.
Simmons received a total of 384 points, including 59 first-pace votes, from a panel of 123 sportswriters and broadcasters throughout the United States and Canada. Miami’s Dwyane Wade finished second with 129 points (15 first-place votes) followed by Detroit’s Tayshaun Prince with 107 points (14 first-place votes). Players were awarded five points for each first-place vote, three points for each second-place vote and one point for each third place vote received.
"Bobby plays the game with toughness," said TNT analyst Doug Collins. "He plays hard. He gives you his best effort all the time. He’s smart. He shoots the ball well and he’s an all-around player."
A former member of the NBDL’s Mobile Revelers, Simmons is in his fourth NBA season and averaged 16.4 points, 5.9 rebounds and 2.7 assists over 37.3 minutes per game this season. He improved his scoring average from last season by 8.6 points, his rebounding average by 1.2 rpg. Simmons also increased his field goal percentage to .466 (up from .394 in 2003-04) and three-point field goal percentage to .435 (up from .167 in 2003-04).
He started 74 of the 75 games in which he played for the Clippers this season, leading the team in scoring on 12 occasions, rebounds five times, assists six times and steals 21 times.
A second round selection in the 2001 NBA Draft (42nd pick overall) by the Seattle SuperSonics, Simmons spent two seasons with the Washington Wizards (2001-02 and 2002-03) before signing with the Clippers prior to the 2003-04 season.
2004-05 NBA MOST IMPROVED PLAYER AWARD VOTING RESULTS
ALL-TIME NBA MOST IMPROVED PLAYER AWARD WINNERS
1985-86: Alvin Robertson, San Antonio